Math, asked by hasraka42, 5 months ago

in a flood relief camp there is a provision for food for 4000 people for 190 days after 30 days 800 people went always elshwere . find for the remaining people in the camp​

Answers

Answered by Anonymous
5

Answer:

4000/190=3200/x

x=3200x190/4000%-152

therefore the food will last for 152 days

Answered by RvChaudharY50
12

Correct Question :- In a flood releif camp, there is provision for 4000 persons for 190 days . After 30 days 800 person shifted to a different place. Find, how long will the remaining food be served to the remaining persons ?

Solution :-

we know that,

  • M1 * D1 = M2 * D2

given that,

  • M1 = 4000 persons .
  • D1 = Days left = 190 - 30 = 160 days.
  • M2 = Person left = 4000 - 800 = 3200 persons .
  • D2 = Let x days.

then, putting all values we get,

→ 4000 * 160 = 3200 * x

→ 4000 = 20x

→ x = 200 days. (Ans.)

Hence, the remaining food be served to the remaining persons for 200 days.

Learn more :-

Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining wo...

https://brainly.in/question/21025557

Shivam alone can do a work in 12 days and Maanik alone can do it in, 15 days. Both started the work together and after w...

https://brainly.in/question/14687371

Similar questions