Math, asked by Ashi567, 10 months ago

In a flower bed, there are 25 rose plants in the first row, 23 in the second, 21 in the third and so on. There are 3 rose plants in the last row. (i) How many rows are there in the flower bed? (ii) Find the total number of rose plants in the flower bed.

Answers

Answered by ramgsa
5

Answer:

(i)12  (ii) 168

Step-by-step explanation:

1st row 25, 2nd row 23 and so on .. nth row 3

they are in A.P with a=25 and d= -2

We know nth term in A.P is given by

Tn = a+(n-1)d

3= 25 + (n-1)(-2)

2(n-1)=22

n=12

total number of rows = 12

total number of rose plants = sum of A.P

Sum of A.P = (n/2)[2a+(n-1)d]

Here, a=25,d=-2 n=12

total number of rose plants = 6[50-22]

                                             =  6[28]=168

Hope it is helpful

Answered by dhukd1234
2

Answer:

(i)12  (ii) 168

Step-by-step explanation:

1st row 25, 2nd row 23 and so on .. nth row 3

they are in A.P with a=25 and d= -2

We know nth term in A.P is given by

Tn = a+(n-1)d

3= 25 + (n-1)(-2)

2(n-1)=22

n=12

total number of rows = 12

total number of rose plants = sum of A.P

Sum of A.P = (n/2)[2a+(n-1)d]

Here, a=25,d=-2 n=12

total number of rose plants = 6[50-22]

                                            =  6[28]=168

Hope it is helpful

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