in a following figure ABCD is a parallelogram in which DC is equal to 6 cm and AE is perpendicular to DC AE is equal to 4 cm find the area of DCF
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DC= 6 cm
AE= 4 cm
As parallelogram ABCD and DFC are between same base[DC] and between same parallel [AB//DC] Therefore area of triangle is equal to half the area of parallelogram.
Now,
1 /2 Area of //gm ABCD = area of triangle DCF
1/2 × AE×DC=area of triangle
1/2 ×6×4 = area of triangle 12 cm² =area of triangle DCF
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