Math, asked by vanyagupta16jan2012, 6 hours ago


In a food festival, Stall A sold 208 burgers and Stall B sold 3 times as
many burgers as Stall A. Stall C sold 85 fewer burgers than Stall B.
How many burgers did Stall B sell?
How many burgers did Stall C sell?

Answers

Answered by ishitmittal03
6

Answer:

STALL B SOLD 624 BURGERS BECAUSE 208*3 = 604

STALL C SOLD 529  BURGERS BECAUSE 624-85 = 529

Step-by-step explanation:

MARK AS BRAINLIEST

Answered by Anonymous
43

\begin{gathered}{\underline{\underbrace{\Huge{\bigstar{\textsf{\textbf{\blue{Solution :}}}}}}}}\end{gathered}

 \orange{\large \qquad \boxed{\boxed{\begin{array}{cc} \footnotesize \tt{Number  \: of  \: Burgers  \: Stall  \: A  \: sold = 208  \: Burgers} \\ \\\footnotesize \tt{Number  \: of  \: burgers \:  Stall  \: B  \: sold = 3 \:  times \:  of  \: Stall  \: A}  \\ \\    \footnotesize \tt{ \implies3 × 208} \\  \\ \footnotesize \tt{ \implies   624 \:  Burgers } \\  \\   \footnotesize \tt{Number  \: of \:  Burgers \:  Stall }  \\   \footnotesize \tt {C \:  sold =  85 \:  less  \: than  \: Stall  \: B (624)} \\  \\  \footnotesize \tt{ \implies 624 - 85 } \\  \\ \footnotesize \tt{ \implies 539 \:  Burgers} \\  \\ \footnotesize \tt{Therefore,  \: Number  \: of } \\   \footnotesize \tt {Burgers \:  Stall  \: C  \: sold \:  is \:  539.} \end{array}}}}

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