Question

in a forest a big tree got broken due to heavy rain and wind . due to this rain the big branches AB and AC with length of 5cm fell down on the ground. Branches AC makes an angle of 30° with the main tree AP. The distance of the point B from P is 4cm. you can observe that ∆ABP is congruent to ∆ACP:
THEN ANSWER THE FOLLOWING
what is the value of angle APC
what is the length of AP ​

Answer 1

Answer:

this is you answer hope it help you

Answer 2

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.