Question

In a four cylinder, four stroke, diesel engine operating at 1200 rpm, the duration of fuel injection is 20°.
The time in seconds during which fuel is injected
would be
​

Answer 1

Answer:

1200 rpm equals one revolution in 60/1200 sec = 3/60 sec

In four stroke engine fuel injection that is part of power stroke that lasts a stroke that is half a revolution of 180 deg.

Thus duration of power stroke = 3/60 * 2 seconds

Thus duration in seconds of fuel injection of 20 deg = 20/180 X 3/60*2 seconds

= 1/9 X 3/120 = 1/9 X 1/40 = 1/360 = 3 milliseconds

Hope it helps you.