Question

In a four sided Field , the length of the longer diagonal is 120 m.The lengths of perpendiculars from the opposite vertices on the diagonal are 20 m and 15 m. find the area of the field.

Answer 1

Let ABCD be the field and AC be it's longer diagonal.

Let BL perpendicular AC and DM perpendicular AC. Then ,



AC = 120 m , BL = 20 m


And, DM = 15 m


Area of the field = [ 1/2 × ( BL + DM ) × AC ] c
m².



=> ( 1/2 × ( 20 + 15 ) × 120 m².


=> 2100 m².

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hello Friend}}}$

Diagonal is = 120m

I Attitude on the diagonal. = 20m
I Attitude on the diagonal = 15m

Area of the Quadrilateral field = 1/2 (Diagonal x Sum of attitude on a diagonal drawn from other vertices)
$= \frac{1}{2} \times (120 \times (20 + 15)) \\ = \frac{1}{2} \times (120 \times 35) \\ = 60 \times 35 \\ = 2100 \: m {}^{2}$
So The area of field is 2100 square meter

$\huge{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{Hope \:it\: helps\: you}}}}}}}}}$