Question

In a Fourier series for f(x) =|sin x| in (π,-π) the value of is

Answer 1

Given f(x) = |sinx|

f(x) = |sinx| = sinx

f(-x) = |sin(-x)| = sinx

Hence f(x) = f(-x)

∴ |sinx| is even function

The Fourier series of an even function contains only cosine terms and is known as Fourier Series and is given by

f(x)=a02+∑n=1∞ancosnx

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