In a fraction :
2 is a numerator
and
![\sqrt[3]{9} + \sqrt[3]{3} + 1 \: \: \: is \: the \: denominator. \:](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B9%7D++%2B++%5Csqrt%5B3%5D%7B3%7D++%2B+1+%5C%3A++%5C%3A++%5C%3A+is+%5C%3A+the+%5C%3A+denominator.+%5C%3A+ "\sqrt[3]{9} + \sqrt[3]{3} + 1 \: \: \: is \: the \: denominator. \:")
The result obtained is
![\sqrt[3]{a} + b \:. \: \: \: \: \: find \: the \: value \: of \: a \: and \: b](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7Ba%7D++%2B+b+%5C%3A.+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+find+%5C%3A+the+%5C%3A+value+%5C%3A+of+%5C%3A+a+%5C%3A+and+%5C%3A+b "\sqrt[3]{a} + b \:. \: \: \: \: \: find \: the \: value \: of \: a \: and \: b")
Answers
Answered by
0
Answer:
2 &3 is the answer for this question
Hope it helps you
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