In a fraction, twice the numerator is 2 more than the denominator. If 3 is added to the numerator and to the denominator, the new fraction is 2/3. Find the original fraction.
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Answer:
Let the numerator be x and denominator be y.
ATQ,
2x=2+y
y=2x-2 (1)
Also,
x+3/y+3= 2/3
x+3/2x-2+3 =2/3 (from (1))
Cross multiplying both sides, we get
3(x+3)= 2(2x+1)
3x+9=4x+2
9-2=4x-3x
7=x
y= 2x-2= 2*7-2=14-2
y=12
Fraction=7/12
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