In a fraction, twice the numerator is 2 more than the denominator.
If 3 is added to the numerator and to the denominator, the new fraction is 2/3. Find the original fraction?
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2
let the numerator be x
denominator = 2x-23 is added :-Numerator= x+3
Denominator= 2x-2+3
=2x+1x+3/2x+1
=2/33(x+3)
=2(2x+1)3x+9
=4x+23x-4x
=2-9-x
=-7-x
SO,
Original Numerator = x
= 7
SO,
Original Denominator = 2x-2
= 2(7)-2
= 14-2
= 12
SO,
Original Fraction = 7/12
denominator = 2x-23 is added :-Numerator= x+3
Denominator= 2x-2+3
=2x+1x+3/2x+1
=2/33(x+3)
=2(2x+1)3x+9
=4x+23x-4x
=2-9-x
=-7-x
SO,
Original Numerator = x
= 7
SO,
Original Denominator = 2x-2
= 2(7)-2
= 14-2
= 12
SO,
Original Fraction = 7/12
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