Math, asked by callmehsarayu, 4 days ago

In a fraction, twice the numerator is 2 more than the denominator. If 3 is added to the
numerator and to the denominator, the new fraction is 2/3. Find the original fraction.

Answers

Answered by Anonymous
15

Answer:

The original fraction is

 \huge\frac{7}{12}

Step-by-step explanation:

Given that

  • In a fraction, twice the numerator is 2 more than the denominator

let the numerator be x

\therefore the denominator is 2x-2

Also

  • If 3 is added to the numerator and to the denominator, the new fraction is 2/3

\implies \large\frac{x + 3}{(2x - 2) + 3}  =  \frac{2}{3}

By cross multiplying we have,

(x+3)3 = 2(2x+1)

3x+9 = 4x+2

4x-3x = 9-2

\therefore x = 7

And

denominator is (2×7)-2 i.e. 12.

Answered by Anonymous
18

Given :

  • Twice the numerator is 2 more than the Denominator .
  • If 3 is added to both numerator and denominator the fraction becomes 2/3 .

 \\ \\

To Find :

  • Original Fraction = ?

 \\ \\

Solution :

 \bigstar According to the Question :

 \longrightarrow Twice the numerator is 2 more than the Denominator .So,

 \qquad \; \large{\underline{\overline{\boxed{\pink{\pmb{\frak{ \dfrac{Numerator}{Denominator} = \dfrac{y}{2y - 2} }}}}}}}

 \\

 \longrightarrow If 3 is added to both numerator and denominator the fraction becomes 2/3 .So,

 \qquad \; \large{\dag{\underline{\overline{\boxed{\pink{\pmb{\frak{ \dfrac{y + 3}{(2y - 2) + 3} = \dfrac{2}{3} }}}}}}}}{\dag}

 \\ \qquad{\rule{150pt}{1pt}}

 \bigstar Let's Cross Multiply :

 {\dashrightarrow{\qquad{\frak{ 3(y + 3) = 2 \bigg\{ (2y - 2) + 3 \bigg\}  }}}} \\ \\ \\ \  {\dashrightarrow{\qquad{\frak{ 3y + 9 = 4y - 4 + 6 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\frak{ 4y - 3y = 9 + 4 - 6  }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\frak{ 4y - 3y = 13 - 6  }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\purple{\pmb{\frak{ y = 7 }}}}}}}}

 \\ \qquad{\rule{150pt}{1pt}}

 \bigstar Calculating the Numerator and Denominator :

 \large{\color{cyan}{\dashrightarrow \; {\underline{\underline{\red{\sf{ Numerator = 7 }}}}}}}

 \\

 \large{\color{cyan}{\dashrightarrow \; {\underline{\underline{\red{\sf{ Denominator = 2y - 2 = 2(7) - 2 = 12 }}}}}}}

 \\ \qquad{\rule{150pt}{1pt}}

 \bigstar Therefore :

❛❛ Original fraction is  {\sf{ \dfrac{7}{12} }} . ❜❜

 \\ {\underline{\rule{300pt}{9pt}}}

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