in a fraction twice the numerator is 22 more than the denominator if 5 is added to the numerator and 1 to the denominator it becomes 1 find the original fraction
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2n=22+d.....eq-1
(5+n)/(1+d)=1.....eq-2
solving equations 1 and 2
2n-d=22
n-d=-4 (-)
n=26
substitute n=26 in equation 1
52=22+d
d=30
(5+n)/(1+d)=1.....eq-2
solving equations 1 and 2
2n-d=22
n-d=-4 (-)
n=26
substitute n=26 in equation 1
52=22+d
d=30
RanjanaJha:
if you briefly describe it then I can understand easily
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