IN A FRACTION, twice the numerator is two more than the denominator.if three is added to the numerator and to the denominator ,the new fraction is 2/3. find the original fraction.
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let the numerator be x and denominator be y
acc. to the question,
2x = y+2
2x-y = 2 ------(1)
(x+3)/(y+3) = 2/3
3x+9 = 2y+6
3x-2y = -3 -----(2)
now from (1) y = 2x-2
put value of y in (2)
3x-2(2x-2) = -3
3x-4x+4 = -3
-x = -7
x = 7
and,
y = 12
therefore original fraction is 7/12
hope this helps;p
acc. to the question,
2x = y+2
2x-y = 2 ------(1)
(x+3)/(y+3) = 2/3
3x+9 = 2y+6
3x-2y = -3 -----(2)
now from (1) y = 2x-2
put value of y in (2)
3x-2(2x-2) = -3
3x-4x+4 = -3
-x = -7
x = 7
and,
y = 12
therefore original fraction is 7/12
hope this helps;p
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