Question

In a fraction, twice the numerator is two more than the denominator. If 3 is added to both numerator and denominator, the new fraction formed is 2/3. Find the original fraction.

Answer 1

let the numerator be x

denominator = 2x-2

3 is added :-

Numerator= x+3

Denominator= 2x-2+3

=2x+1

x+3/2x+1=2/3

3(x+3)=2(2x+1)

3x+9=4x+2

3x-4x=2-9

-x=-7

x=7

Original Numerator = x = 7

Original Denominator = 2x-2

= 2(7)-2

= 14-2

= 12

Original Fraction = 7/12

Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

Fraction is $\bold{\frac{7}{12}}$

$\bold\green{\underline{\underline{Solution}}}$

Let the numerator be x and denominator be y.

According to the first condition

2x=y+2

2x-y=2...(1)

According to the second condition

$\bold{\frac{x+3}{y+3}=\frac{2}{3}}$

$\bold{3(x+3)=2(y+3)}$

$\bold{3x+9=2y+6}$

$\bold{3x-2y=-3...(2)}$

Multiply equation (1) by 2

4x-2y=4...(3)

Subtract equation (2) from equation (3), we get

4x-2y=4

-

3x-2y=-3

x=7

Substituting x=7 in equation (1), we get

2(7)-y=2

14-y=2

-y=4-14

-2y=-12

$\bold{y=\frac{-12}{-1}}$

y=12

Fraction is $\bold{\frac{x}{y}}$

i.e $\bold{\frac{7}{12}}$