In a fraction,twice the numerator is two more than the denominator.If 1 is added to the numerator and the denominator each,then the resultant fraction will be 2/3 what was the original fraction
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let numerator be x nd denominator be y.
now, according to the question,
2x = 2 + y
2x - y = 2. (1)
(1 + x) / (1 + y) = 2/3.
3(1 + x) = 2(1 + y)
3 + 3x = 2 + 2y
3x - 2y = -1. (2)
Now, multiplying (1) by 2 ,we get,
4x - 2y = 4. (3)
subtracting both equations,
(4x - 2y = 4) - (3x - 2y = -1)
4x - 3x - 2y + 2y = 4 + 1
x = 5
now putting the value of x in (1)
2(5) - y = 2
10 - y = 2
y = 8
Therefore, the original fraction is 5/8
Hope the answer is correct and helpful tooo.......
now, according to the question,
2x = 2 + y
2x - y = 2. (1)
(1 + x) / (1 + y) = 2/3.
3(1 + x) = 2(1 + y)
3 + 3x = 2 + 2y
3x - 2y = -1. (2)
Now, multiplying (1) by 2 ,we get,
4x - 2y = 4. (3)
subtracting both equations,
(4x - 2y = 4) - (3x - 2y = -1)
4x - 3x - 2y + 2y = 4 + 1
x = 5
now putting the value of x in (1)
2(5) - y = 2
10 - y = 2
y = 8
Therefore, the original fraction is 5/8
Hope the answer is correct and helpful tooo.......
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