Question

in a freq distribution table the mid value of the class is 10 and the width of the class is 6 . The upper class?​

Answer 1

Answer:

13

Step-by-step explanation:

Mid-value = 10

Class size = 6

To find answer :

Divide class size by 2 = 6/2 = 3

Subtract the quotient from mid - value.

10-3 = 7 (This is the lower limit)

Add the quotient to mid-value

10+3 = 13 (This is the upper limit)