Question

In a frequency distribution mid value of a class is 10cm and width of class is 6. Find lower limit of the class

Answer 1

Mid value = 10 cm
Width = 6
Lower Limit = mid value of class - width
                                                            2
                  = 10 - 6
                            2
                   = 10 - 3
                   = 7

Answer 2

Class width = 6
Mid value = 10 cm

Half of Class width =$\frac{6}{2}$
= 3

Lower limit of a class = Mid value - half of class width
= 10 - 3
= 7
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If you were asked to find the upper limit of the class , then ,

Upper limit = Mid value + half of class width
= 10 + 3
= 13