Question

In a frequency distribution table, size of the class is 16 and class mark 20 then upper limit of the class is _____​

Answer 1

Answer:

Step-by-step explanation:

class marks are -

15, 20, 25

STEPS -

1) take out the difference between the given corresponding class marks

the difference between the class marks

= 20- 15

= 5

2) find the mid value of the difference.

now 5/2 = 2.5

3) add and subtract the midvalue with the class mark to obtain the upper and lower class limits.

of the class corresponding to class mark 20:-

upper limit = 20 + 2.5 = 22.5

lower limit = 20 - 2.5 = 17.5

___________________________

therefore

required class = 17.5 - 22.5