Question

in a frequency distribution the class mark of a particular class is 20 and class size is 8 then find the class interval


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Answer 1

Step-by-step explanation:

let the upper limit be X

let the lower limit be Y

class size = 8

class interval = 20

upper class - lower class = class size

x-y = 8................. equation 1 ( x = 8+y)

upper class + lower class/2 = class mark

x + y/2 = 20

8+y + y/2= 20

8+ 2y = 40

2y = 40-8

2y. = 32

y = 32/2

= 16

x = 8+y

= 8+16

= 24

and y = 16