Question

in a frequency distribution, the mid value af a class is 10 and width of each class is 6 find the lower limit of the class

Answer 1

Answer:

Step-by-step explanation:

upperlimit - lower limit = width

upper limit = width + lowerlimit

Upper limit + lower limit/2 = mid value

2lowerlimit + width/2 = midvalue

4lowerlimit + 6 = 20

4lowerlimit = 14

lowerlimit = 3.5