Math, asked by himanshu2006785, 7 months ago

in a frequency distribution the mid value of a class is 10 and the width of the glass is 6 the upper limit of the class is:

Answers

Answered by nikunjc971

5

Step-by-step explanation:

The mid value of the class =10

Width of the interval =6

then lower limit = Mid value−

2

Width

=10−3=7

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