Question

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The upper limit of the class is

Answer 1

Step-by-step explanation:

Given,

Mid value = x

= 10

Class width (h) =6

Lower limit = x - h/2

= 10-6/2 = 10-3 =7

Upper limit = x+h /2

= 10+6/2

= 10+3

= 13

Therefore, Class interval: 7-13

Lower limit = 7

Upper limit = 13