Question

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6.
The lower limit of the class is:
(A) 6
(B) 7
(C) 8
(D) 12

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Answer 1

mid value= 10

class width= 6

lower limit= mid value- width/2
= 10-6/2
= 10-3
= 7

Answer 2

Answer:

Lower limit of the class = mid value of class - width of class / 2 .

⇒ L = 10 - 6 / 2

⇒ L = 10 - 3

⇒ L = 7

Hence the correct answer is OPTION B .

Step-by-step explanation:

We know that the width of the class is Upper limit - Lower Limit .

Width of the class = Upper limit - Lower limit

We also know that when Width of the class is halved then the difference will be halved .

⇒ Width of class / 2 = ( Upper limit - lower limit ) / 2

( Upper limit - lower limit ) / 2 = mid value - lower limit

Hence we have used mid value - lower limit = width of class / 2 .