Question

In a frequency distribution, the mid-value of a class is 20 and the width of the class is 8. Then the lowee class is

A. 12

B. 24

C. 28

D. 16

Answer 1

let the lower limit be  x
 ∴upper limit =(x+8) (∵ class size is 8)
mid value of class =(upper limit +lowerlimt)÷2
⇒20 =[(x+8)+x]÷2
⇒40=2x+8
⇒40 - 8 =2x
⇒32 =2x
∴x =16

Answer 2

Answer:

16

Step-by-step explanation:

Let the lower limit of class be x

We are given that the class width is 8

So, Upper limit of class = x+8

Now we are given that  the mid-value of a class is 20

So, Mid point formula = $\frac{\text{upper limit} +\text{lower limit}}{2}$

Substitute the values :

$20 = \frac{x+8+x}{2}$

$40 = 2x+8$

$40 - 8= 2x$

$32= 2x$

$16= x$

Hence lower limit of class is 16

So, Option D is true.