Question

in a frequency distribution, the mid value of class 27.5 and the width of the class is 5. find the upper limit​

Answer 1

Answer:

given,

(Upper limit+Lower limit)/2=27.5

Upper limit+Lower limit=2×27.5=55•••eq.1

Also,

Upper Limit - Lower limit=class width=5•••eq.2

On adding eq.2 amd eq.1,we get:

Upper limit+lower limit+upper limit-lower limit=55+5

2Upper limit=60

So,Upper limit=30.

Answer 2

The answer = 30

Given: The mid value of class = 27.5

Width of the class = 5

To find: Upper limit of the class

Solution:

To find the upper and lower limit of a class we will use following formulas

Lower limit=  $[a - \frac{h}{2} ]$

Upper limit = $[a +\frac{h}{2} ]$    where a is mid value and h is class width  

From given data  a = 27.5 and h = 5

⇒ Upper limit = $[27.5+\frac{5}{2} ]$ = 27.5+ 2.5 = 30

Upper limit = 30

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