In a fruit basket the oranges and bananas are in the ratio 2:3. 15% of oranges are rotten and 10% of bananas are rotten. if a fruit is selected at random, then what is the probability that it will be rotten?
Answers
Answered by
1
sum of 2 and 3 is 5
sum of 10 and 15 is 25
probability of getting rotten orange is 5/25*3
so, 3/5
probability of getting rotten bananas is 5/25*2
so, 2/5
hope it helps.....
plz mark brainliest.......
sum of 10 and 15 is 25
probability of getting rotten orange is 5/25*3
so, 3/5
probability of getting rotten bananas is 5/25*2
so, 2/5
hope it helps.....
plz mark brainliest.......
cherylsmathew:
it is wrong
the final answer is 3/25..... i dont know how to solve it
can anyone else help.... its urgent
yes, I got it
ratio is 2 and 3 so, 10 percent plus 15 percent so it is 25 the probability of orange is 3/25and probability of banana is 2/25
did u get
Answered by
5
Let the common ratio be x
Total fruits=2x + 3x = 5x
Rotten oranges
15/100 × 2x = 3x/10
Rotten Bananas
10/100 × 3x = 3x/10
Total rotten fruits
3x/10 + 3x/10 = 3x/5
Probability
3x/5 / 5x = 3/25
Total fruits=2x + 3x = 5x
Rotten oranges
15/100 × 2x = 3x/10
Rotten Bananas
10/100 × 3x = 3x/10
Total rotten fruits
3x/10 + 3x/10 = 3x/5
Probability
3x/5 / 5x = 3/25
Similar questions