in a G.p the 3rdterm is 24 and 6th term is 192 find the 10th term
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3rd term of the GP = 24 = ar2
6th Term of the GP = 192 = ar5
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Hence,
6th term / 3rd term = ar5 / ar2 = 192 / 24
r3 = (192) / (24)
r3= (2*2*2*2*2*2*3) / (2*2*2*3) = (23)
Hence, r = 2
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Since, ar2 =24
a(2)2 = 24
a = 24/4 = 6
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Hence first term, a = 6, and r = 2.
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Hence, the 10th term = ar10-1 = ar9
10th term = (6)(2)9 = 6(2)8 (2) = 6(4)4 (2) = 6(16)2 (2) = (6)(256)(2) = 3072,
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Hence the 10th term = 3072.
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