In a g.p. the third term is 24 and 6th term is 192. find the 10th term
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As general term of gp series is ar ^n-1
So 3rd term = ar^2= 24
and 6th term = ar^5 = 192
Dividing we get, r^3 = 8
So r = 2
putting r in any equation we get a = 6
So 10th term = ar^9 = 6* 2^9 = 6*512 = 3072
So 3rd term = ar^2= 24
and 6th term = ar^5 = 192
Dividing we get, r^3 = 8
So r = 2
putting r in any equation we get a = 6
So 10th term = ar^9 = 6* 2^9 = 6*512 = 3072
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