In a G. Pa= v5, r= 2v5 find T5
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Answer:
in this GP series,
T5=ar^(n-1)
here a=√5
r=2√5
n=5
T5=√5.(2√5)^(5-1)
=√5.(2√5)^4
=√5.16.25
=400√5
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