Question

In a galvanometer there is a deflection of 1.0 divisions per Ma.the internal resistance of the galvanometer is 60ohm . if a shunt of 2.5 ohm is connected to the galavometer ,calculate the the maximum current in which the galvanometer can be dead.

Answer 1

Explanation:

sorry bro i dont know i m secondary class sorry to say it

Answer 2

The maximum current in which the galvanometer can be read is 125 mA

- Given:

deflections per mA =  0.1 divisions

G = 60 Ω

S = 2.5 Ω

-the galvanometer has 50 divisions, so for full scale division, current required

 $I_{g}$ = deflections per mA × no. of divisions

     = 0.1 × 50

 $I_{g}$ = 5 mA

-let I be the maximum current that galvanometer can read

- then

$I_{g}$ × G = (I- $I_{g}$)S

on substituting the given values in it, we get

5 × 60 = (I-5) 2.5

300/2.5 = I - 5

120 = I -5

 I = 125 mA