Math, asked by parminderkaur91, 10 hours ago

In a game, a number is chosen at random from the set {1,2,3,…, 28,29,30}. What is the probability that the number chosen is a product of exactly two different prime numbers.

Answers

Answered by surbhisem
5

Step-by-step explanation:

If there were no prime numbers is this or any set of numbers, the odds are the number of possible results divided by 1, or 30 to 1. The number of prime numbers in the set 1 to 30 are 10: 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29. So 30 divided by 10 = 3 to 1

Answered by nithya202020
1

Answer:  7/30

Step-by-step explanation:

The total number of outcomes is equal to 30.

The favorable outcomes are (6,10,14,22,26,15,21)

Therefore, number of favorable outcomes is 7.

Let the probability that the number chosen at random is a product of exactly two different prime numbers be p(E)

P(E) = no of favourable outcomes/ total no of outcomes

       =7/30

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