Question

In a game of cards . Neeraj score 3 more than twice no.of coins Pankaj scores . If the product they score is 65 how many coins each have

Answer 1

let the no. of points scored by Pankaj be x 
the no. of point scored by neeraj=2x+3 according to the question
x(2x+3)=652x^2+3x=652x^2+3x-65=02x^2-10x+13x-65=02x(x-5)+13(x-5)=0(2x+13) (x-5)x=-13/2(not possible) x=5points scored by pankaj = 5points scored by neeraj =2(5)+3=13

Answer 2

Let Pankaj score x
Neeraj's score = 2x + 3
X ×( 2x +3) = 65
2x^2 + 3x -65 =0
2x^2 - 10x + 13x -65 =0
(2x + 13) (x - 5) = 0
x = -13/2 is rejected
x = 5
So pankaj scores 5, neeraj scores 13