In a game of chance, a spinning arrow comes to rest at
one of the numbers 1. 2. 3. 4. 5. 6. 7. 8.
All these are equally likely outcomes
To find the probability that it will rest at 8.
Let A be the event that arrow points at the number 8
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Given : In a game of chance, a spinning arrow comes to rest at
one of the numbers 1. 2. 3. 4. 5. 6. 7. 8.
All these are equally likely outcomes
To find : the probability that it will rest at 8.
Let A be the event that arrow points at the number 8
Solution:
S = { 1, 2, 3, 4, 5, 6, 7, 8 }
=> n(S) = 8
A be the event that arrow points at the number 8
=> A = { 8 }
=> n(A) = 1
P(A) = n(A)/n(S)
=> P(A) = 1/8
probability that it will rest at 8. = 1/8
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