Math, asked by vinuthatanmayi29, 3 months ago

In a game of chance consisting of spinning an arrow which comes to rest pointing atone
of the numbers 1. 2. 3,
20 (see Fig. 34) and these are equally likely outcomes. Three
persons Aarushi, Avni and Mira decide to play the game. Aarushi wins 5000 if the
arrow points at an even number. Mira wins 5000 when arrow points at an odd number
and Avni wins 7 12,000 when arrow points at a prime number. Based on the above
information answer the following questions:
12
11 10
9
13
8
14
7
15
6
16
01
17
4
18
3
19
20 1
2
50
% على
Fig. 34
Total number of possible
outcomes in the game is
(a) 10
120
(c) 30
(d) 40
What are the chances of Aarushi winning + 5000?
(a) 50%
(b) 60%
(c) 40%
(d) 25%
What are the chances of Mira winning * 3000?
(a) 60%
(b) 40%
%
(d) 80%
What are the chances of Avni winning * 12000?
(a) 50%
(b) 60%
(c) 80%
(dy 40
What are the chances of Mira and Avni winning their prize money?
(a) 35%
(b) 5%
(c) 40%
(d) 25%
What are the chances of Aarushi and Avni winning their prize money?
(a) 35%
(b) 5%
(c) 10%
(d) 20%
Chances of all three winning their prizes are?
(a) 5°
(b) 10%
(c) 1%
(d) 0%​

Answers

Answered by amitnrw
13

Given : game of chance consisting of spinning an arrow which comes to rest pointing atone of the numbers 1. 2. 3,  _____ ,20

equally likely outcomes.

Aarushi wins 5000 if the arrow points at an even number.

Mira wins 5000 when arrow points at an odd number

Avni wins  12,000 when arrow points at a prime number.

To Find : Total number of possible outcomes in the game

chances of Aarushi winning

chances of Mira winning

chances of Avni winning

chances of Mira and Avni winning their prize money

chances of Aarushi and Avni winning their prize money

Chances of all three winning their prizes are

Solution:

Total possible out comes  = 20    ( 1 to 20)

Aarushi wins 5000 if the arrow points at an even number.

there are 10 even numbers ( 2 , 4 , 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20)

chances of Aarushi winning   5000  = (10/20) * 100 = 50 %

There are 10 odd numbers ( 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 , 17 , 19(

chances of Mira winning   = (10/20) * 100 = 50 %

8  Prime numbers 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19    

chances of Avni wins   = (8/20) * 100 = 40 %

chances of Mira and Avni winning     ( 3 , 5 , 7 , 11 , 13 , 17 , 19 )  = 7 numbers

= (7/20) * 100 = 35 %

hances of Aarushi and Avni winning their prize money  = only number 2

Hence ( 1/20) * 100 = 5 %

Chances of all three winning their prizes are  = 0 %

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Answered by huguj2916
4

Answer:

Total possible out comes = 20

(1 to 20)

Aarushi wins 5000 if the arrow points at an even number.

there are 10 even numbers (2,4,6,8,10,12,

14.16.18.20)

chances of Aarushi winning 5000 = (10/20) *

100 = 50 %

There are 10 odd numbers (1,3,5,7,9,11,13,

15, 17, 19( chances of Mira winning = (10/20) * 100 = 50 %

8 Prime numbers 2,3,5,7,11,13,17,19 chances of Avni wins (8/20)*100=40%

chances of Mira and Avni winning (3.5.7. 11.13.17, 19) = 7 numbers

=(7/20) * 100 = 35 %

hances of Aarushi and Avni winning their prize money only number 2

Hence (1/20) * 100 = 5%

Chances of all three winning their prizes are = 0

Step-by-step explanation:

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