Question

in a game of chance the probability of winning is 1/3.what is the probability of losing​

Answer 1

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Given,

P(Winning) = 1 / 3

We know,

P(E) + P(not E) = 1

So P(not winning) = 1 - ( 1/3 )

P(losing) = 2 / 3

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Answer 2

Answer:

1-1/3=2/3

Step-by-step explanation:

let probility of wining game is 1

probility of losing game is 1-1/3

thanks have a learning day