Question

in a game of chance there is spinning of an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and there are equally likely outcomes. What is the probability that it will point at (i) 7? (ii) an odd number? (iii) a number less than 9?

Answer 1

Answer:

(i) $\frac{1}{2}$

(ii) $\frac{5}{8}$

(iii) 1

Step-by-step explanation:

Size of sample space = 8

(i) Number of odd numbers = 4

Therefore, probability of an odd number = $\frac{4}{8}$

or,   $\frac{1}{2}$

(ii) Number of number greater than 3 = 5

Therefore, probability of a number greater than 3= $\frac{5}{8}$

(iii) Number of numbers less than 9 = 8

Therefore, probability of a number lesser than 9= $\frac{8}{8} = 1$

__________________________________________________________

Answer 2

$\pmb{\sf{Question :}}$

In a game of chance there is spinning of an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and there are equally likely outcomes. What is the probability that it will point at

(i) 7

(ii) an odd number

(iii) a number less than 9

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\pmb{\sf{Formula :}}$

${ \underline{ \boxed{ \sf {Probability = \frac{favourable \: outcomes}{total \: no. \: of \: outcomes} }}} }$

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\pmb{\sf{Solution :}}$

$\hookrightarrow \text{Total no. of outcomes = 8}$

$\bigstar \: \sf{ P(getting \:7) = \frac{1}{8}}$

$\text {\footnotesize\fcolorbox{red}{b}{7 occurs only once from 1 to 8}}$

$\bigstar \: \sf{P(odd \: number)= \frac{4}{8}=\frac{1}{2}}$

$\text {\footnotesize\fcolorbox{red}{b}{Odd numbers from 1 and 8 = 1,3,5,7}}$

$\bigstar \: \sf{P(a \: number \: less \: than \: 9) = \frac{8}{8}=1}$

$\text {\footnotesize\fcolorbox{red}{b}{All numbers from 1 to 8 are less than 9}}$

$\sf \color{azure}\fcolorbox{pink}{black}{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: @Saanvigrover2007 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:}$