Question

In a game of chance there is spinning of an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and there are equally likely outcomes. What is the probability that it will point at 7? *​

Answer 1

Answer:

Given that,

Number of events =1,2,3,4,5,6,7,8

Total numbers n(S)=8

Factor of 8=1,2,4 and 8

Number of factor n(E)=4

Therefore,

Probability=

n(S)

n(E)

=

8

4

Probability=

2

1

.