Question

In a game of cricket, the score of team with respect to wickets follows arithmetic progression first wicket fall on 35 score, second fall on62 , third on 89 What will be the final score of team

Answer 1

Answer:

The final score of the team will be 278 runs.

Step-by-step explanation:

The First wicket falls on 35, 2nd on 62, 3rd on 89 and so on it forms an AP. Hence the first inning will be over when 10 wicket will fall down, Hence we have to calculate the 10th term of the AP.

Given,

First term = a = 35

common difference, d = 62 - 35 = 27

n = 10

So,

a₁₀ = a + (n-1)d

=> a₁₀ = 35 + 9x27

=> a₁₀ = 278

Hence the final score of the team will be 278 runs.

Answer 2

Step-by-step explanation:

The given series is 35,62,89,.......

For the final score the number of wickets will be 10

∴ We need to find T

10

.

We have,

a=35,d=62−35=27,n=10

T

n

=a+(n−1)d

=35+(10−1)27

=35+9(27)

=35+243

=278

∴ The final score of the team is 278 runs

October 15, 2019