Math, asked by brainsout99, 1 month ago

in a game, the entry fee is 5. The game consists of a tossing a coin 3 times If one or two heads show, Sweta gets her entry fee back. If she throws 3 heads, she receives double entry fees. Otherwise she will lose. For tossing a coin three times, find the follow...

1 . What is the total number of outcomes for this game

2 . Probability that she loses the entry fee

3 . Probability that she gets double entry fee

4 . Probability that she just gets her entry fee

5 . Sum of probability in all the above three cases​

Answers

Answered by sachinjosyulayn
1

Answer:

One coin is tossed 3 times so total number of favourable outcomes =23=8, which are (HHH),(HHT), (THH) and (replacing H→TandT→H) (TTT),(TTH),(THT),(HTT). (i) Losing the game means getting no head. So, probability (losing the entry fee) i.e., P(E)=F(E)T(E)=18 ltbr. (ii) Gets double entry fee back by getting 3 heads

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