Question

In a garden, roses and marigolds are planted in a square plot. The length of the square plot in which roses are planted is 2 metres greater than the length of the square plot in which marigolds are planted. How much bigger in area ia the rose plot than marigold plot?

Answer 1

area of a square = length*length 
let the length of marigolds = l
so the length of roses = 2+l
the area of marigold = l*l = $l^{2}$
the area of roses = (2+l)*(2+l)
= 4+$l^{2}$+4l
so the difference between the two gives how big area is the rose plant 
= 4+$l^{2}$+4l -$l^{2}$ = 4+4l
so its area is 4times 1+it length greater

Answer 2

Let the length of plot with marigold be = x metre
So length of plot with rose = x+2 metres

We know that area of square = side^2

Area of marigold plot= x^2
Area of rose plot = (x+2)^2
= x^2 + 2(x)(2) + 2^2
= x^2 + 4x +4

Difference = x^2 +4x+4 -(x^2)
= 4x+4 m^2

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