In a garden, roses and marigolds are planted in a square plot. The length of the square plot in which roses are planted is 2 metres greater than the length of the square plot in which marigolds are planted. How much bigger in area ia the rose plot than marigold plot?
Answers
Answered by
28
area of a square = length*length
let the length of marigolds = l
so the length of roses = 2+l
the area of marigold = l*l =
the area of roses = (2+l)*(2+l)
= 4++4l
so the difference between the two gives how big area is the rose plant
= 4++4l - = 4+4l
so its area is 4times 1+it length greater
let the length of marigolds = l
so the length of roses = 2+l
the area of marigold = l*l =
the area of roses = (2+l)*(2+l)
= 4+
so the difference between the two gives how big area is the rose plant
= 4+
so its area is 4times 1+it length greater
yoursforever16p0loe7:
Answer is satisfying but last statement is confusing......plz make it clear
i meant the answer is 4+4l so by taking 4 common answer is 4(1+l) thats it
if u r satisfied mark me as brainlest
Answered by
25
Let the length of plot with marigold be = x metre
So length of plot with rose = x+2 metres
We know that area of square = side^2
Area of marigold plot= x^2
Area of rose plot = (x+2)^2
= x^2 + 2(x)(2) + 2^2
= x^2 + 4x +4
Difference = x^2 +4x+4 -(x^2)
= 4x+4 m^2
If you satisfied mark it brainliest.
So length of plot with rose = x+2 metres
We know that area of square = side^2
Area of marigold plot= x^2
Area of rose plot = (x+2)^2
= x^2 + 2(x)(2) + 2^2
= x^2 + 4x +4
Difference = x^2 +4x+4 -(x^2)
= 4x+4 m^2
If you satisfied mark it brainliest.
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