Question

In a gemetric progression, the sum of the first two terms is -4 and the fifth term is four times the third term. Find the gemetric progression

Answer 1

Given :-t1 +t2 = -4...................(1)
&t5 =4×t3.....................(2)
Solution:- tn=a+(n-1)d.............(3)
[a+(1-1)d]+[a+(2-1)d]=-4
[a+(0)d]+[a+(1)d]=-4
a+a+d=-4
2a+d=-4.........................(4)

[a+(5-1)d] =4×[a+(3-1)d]
a+4d=4(a+2d)
a+4d=4a+8d
3a+4d=0
3a=-4d
3a/d=-4.......................(5)
from (4) &(5) ,
2a+d=3a/d
2ad+d×d=3a
2ad+d2=3a
d(2a+d)=3a




sorry but now i lam confused
i will think and give answer afterwards