Question

In a general election between two candidates, the total number of expected voters was 10,000. while voter turnout was 78%, the winning candidate got 65% of the votes. by how many votes did the second candidate lose the election?​

Answer 1

Answer:

2730

Step-by-step explanation:

78% of 10000 is 7800

65% of 7800 is 5070

winner gets 5070

looser got 7800-5070= 2730

Answer 2

The answer is 2340 votes.

GIVEN

In a general election between two candidates, the total number of expected voters was 10,000. while voter turnout was 78%, the winning candidate got 65% of the votes.

TO FIND

By how many votes did the second candidate lose the election.

SOLUTION

We can simply solve the above problem as follows;

Total number or expected voters = 10,000

Voter turnout percentage = 78

Number of voters who turned out = 78% of 10,000 = 7,800.

Percentage of votes to winning candidate = 65%

Number of votes to winning candidate = 65% of 7,800 = 5070

Number of votes to losing candidate = 7800-5070 = 2730.

The losing candidate lost the election by 5070-2730 = 2340 votes.

Hence, The answer is 2340 votes.

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