in a geometric progression second term is 6 and fifth term is 48 find the 10th term
step by step answer
Answers
In triangle ABC, if D is any point on side BC, show that AB+BC+CA>2AD?
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5 ANSWERS
Ved Prakash Sharma
Ved Prakash Sharma, former Lecturer at Sbm Inter College, Rishikesh (1971-2007)
Answered Jul 14 2018 · Author has 4.6k answers and 859.9k answer views
We know that:-
In a triangle sum of two sides is always greater
than the third side.
In truangleABD
AB+BD > AD…………….(1)
In triangle ADC
DC+CA > AD…………….(2)
On adding (1) & (2)
AB+BD+DC+CA > 2AD
On putting BD+DC=BC
AB+BC+CA > 2AD . Proved
Answer:
Step-by-step explanation:
Let the first term be a and common ratio be r.
ATP,
ar=6
and,
ar^4=48
ar*r^3=48
6r^3=48
r^3=8
r=cbrt(8)=2
Thus, a=6/r=6/2=3
Therefore 10th term=3*2^(10-1)
=3*512
= 1536