Question

.In a Geometric Progression,the third term is 3/16&6th term is 24. Then the 20th term is

Answer 1

HERE'S YOUR ANSWER



T3 = a.r^2 = 3/16 ____1

T6 = a.r^5 = 24 _____2

Dividing 2 by 1 , we get

r^3 = 128

=> r = cube root 128

Putting value of r in 1, we get

a.(cuberoot128)^2 = 3/16

Find the value of a from.here.

Now, T20 = a.r^19

put the values of a and r in the equation and you will get the 20th term.



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