in a geometric progretion the 5th term is 9 X3rd term and the sum of 6th and 7th terms is 1944 . Determine ;
A The common ratio
B The first term
C The sum of 4th to 10th terms inclusive
Answers
Answered by
0
Answer:
a
Step-by-step explanation:
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Answered by
1
Answer:
a) common ratio
b) sum of the first 6 terms
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Answer by richwmiller(17219) About Me (Show Source):
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a)
common ratio r=3
b)
Tn = T1 * r^(n - 1)
T7 = T1 * 3^(6)
T6 = T1 * 3^(5)
T7 +T6 =972
T1 * 3^(5)+ t * 3^(6)=972
T1*(3^5+3^6)=972
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