In a given circle with centre o if angle ∠abc = 95 degree angle ∠acd= 60 degree and cd is a tangent to C find angle ∠adc and ∠dct
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∠ADC =180°-95°( opposite angles in a cyclic quadrilateral are supplementary )
∠ADC=85°
∠CAD = 180°-60° -85°
∠CAD= 180°-145°
∠CAD= 35°
∠DTC=∠CAD=35°( The angle between a tangent and chord through the point of contact is equal to an angle in the alternate segment )
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