Question

in a given figure a parallelogram ABCD and PVC Q are given if R is a point on P B then show that area of triangle QRS is equal to half of area of parallelogram ABCD​

Answer 1

Answer:

Step-by-step explanation:We know that if 2 quad.s are on same base and b/w same parallel lines then the areas of both quad.s are equal.

Therefore ,ar(ABCD)=ar(PBCQ)

So we get. ,, 1/2ar(ABCD)=1/2ar(PBCQ)......(1)

In quad. PBCQ

We know when a quad. and a triangle are on same base (QC) and are in same parallel lines (QC and PB) then the area of triangle is half of the area of quad.

So ...ar(QRC)= 1/2ar(PBCQ).......(2)

From (1) and (2)

ar(QRC)=1/2ar(ABCD)