Question

in a given figure AB=AC and angle of BAC =40 then the sum of find angle of adc and dac​

Answer 1

since the figure has 3 sides so we get to know that it's a triangle and an iscoseles one . SO

ATQ

other angles be x,x

x+x+40=180

2x=140

x=70

Answer 2

Answer:

In traingle ABC

AB=AC, hence, ∠ABC=∠BCA

Given, ∠BAC=40

∠ABC+∠BCA+∠BAC=180

∠ABC=∠BCA=

2

180−40

=70

therefore, ∠BCA=70

∘

Now, ∠ACD+∠ACB=180

∠ACD=110

In ΔACD,

∠ACD+∠DAC+∠ADC=180

∠DAC+∠ADC=70

Step-by-step explanation:

Hope it is helpful .