Question

in a given figure ABC is an isosceles triangle with AB=AC.Prove that E is the mid point of BC.
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Answer 1

Answer:

AD=AE(Tangents from outside point)

BD=BE(Same logic)

CF=CE(Same logic)

BD=AB - AD

CF=AC - AF

AB=AC, AD=AF

So, BD=CF

BD=BE & CF=CE

So, BE=CE

BC=BE + CE

BC=2*BE

BE=(1/2)*BC

Thus, E is the midpoint of BC.